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(Hmmm, does "21" refer to Blackjack or Ben's age?) The Monty Hall Problem One solves this problem by comparing the probability of choosing the car if you.


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blackjack math problem

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(Hmmm, does "21" refer to Blackjack or Ben's age?) The Monty Hall Problem One solves this problem by comparing the probability of choosing the car if you.


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blackjack math problem

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Keywords. Blackjack. Serendipitous hand. Probability models The question is examined here by comparing results from the two kinds of sampling.


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Keywords. Blackjack. Serendipitous hand. Probability models The question is examined here by comparing results from the two kinds of sampling.


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blackjack math problem

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For how to solve the problem yourself, see my smotri-umor.fun site, problem If I play hands of blackjack at $5 a hand at an % house edge how.


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I. Fundamental Probability Issue: True Odds at Blackjack, Software Calculator II. Fundamental Myth of Blackjack Gambling: Counting Cards III. Theory of Streaks:ā€‹.


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You will also find there other issues of probability-based blackjack strategy. See the Books section for details. Check this.


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smotri-umor.fun ā€ŗ ask-the-wizard ā€ŗ blackjack ā€ŗ probability.


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Hence the probability of neither player getting a blackjack is: 1āˆ’+,,ā€‹ Since there are four aces and 16 cards K, the raw probability of a hand being blackjack is: Hopefully this at least helps you contextualize the problem.


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For how to solve the problem yourself, see my smotri-umor.fun site, problem If I play hands of blackjack at $5 a hand at an % house edge how.


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blackjack math problem

Michael Cotton Michael Cotton 3 3 silver badges 6 6 bronze badges. What posts should be escalated to staff using [status-review], and how do Iā€¦. Because the chance of one player getting blackjack is small, the enrichment is small as well, so this is not far off. Your calculation for the first player is correct. Sign up using Facebook. Sign up using Email and Password. Mathematics Stack Exchange works best with JavaScript enabled.{/INSERTKEYS}{/PARAGRAPH} Suppose that you are playing blackjack against the dealer. Blackjack Probability Ask Question. Email Required, but never shown. So I deleted the more complicated answer I tried to give earlier. Sign up to join this community. Home Questions Tags Users Unanswered. The outermost branches are short, but the inside of the tree is massive Hopefully this at least helps you contextualize the problem. Nolohice 5 5 silver badges 12 12 bronze badges. Active 1 year, 7 months ago. MaxWell MaxWell 2 2 bronze badges. The use of neither indicates that. The probability of both getting blackjack is just the probability of the player getting blackjack and the subsequent probability of the dealer also getting blackjack:. Asked 5 years, 3 months ago. This happens every time. Hot Network Questions. {PARAGRAPH}{INSERTKEYS}Mathematics Stack Exchange is a question and answer site for people studying math at any level and professionals in related fields. This is not quite correct, as the fact that the first player did not get blackjack enriches the average deck with cards that could make a blackjack for the second player. Viewed 19k times. I don't know if this will get you any closer to a closed form solution, but maybe it helps you think about it. Related 0. Featured on Meta. With a branching factor of five I know , we have two aces, once ace, two whatevers, one 10, two 10s. I can't help but wonder if there perhaps is a less hideous way of acquiring the same answer though. Question feed. It only takes a minute to sign up. Sign up or log in Sign up using Google. Active Oldest Votes. We're switching to CommonMark. Ross Millikan Ross Millikan k 24 24 gold badges silver badges bronze badges. Then for the other player we either give them two aces from the 3 that are left, give them one ace from the 3 that are left and 1 of the 32 cards, or give them two non-aces from the 47 non-aces that are left. Post as a guest Name. The naive assumption is that the chance of each player getting blackjack is independent of the others. The best answers are voted up and rise to the top.